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February 1st, 2018, 05:41 PM   #1
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Math Focus: I'm still deciding, but my recent focus has been olympiad problems and math journal problems.
How did they get those two equations?

I am just wondering how they went from equation (3) to the pair of equations $3uv+p=0$ and $u^3+v^3=q$. I understand if those are true then the original equation will be true, but I was wondering why they chose $3uv+p=0$ instead of $u+v=0$. Why did they set $u^3+v^3$ equal to $q$?

This step just seems mysterious to me.
Attached Images 27459294_538768059831773_8101723022367454621_n.jpg (65.7 KB, 16 views) February 1st, 2018, 05:51 PM #2 Senior Member   Joined: Oct 2016 From: Arizona Posts: 209 Thanks: 37 Math Focus: I'm still deciding, but my recent focus has been olympiad problems and math journal problems. OMG nevermind since $x=u+v$, then we don't want it to be $0$. Sorry for asking a dumb question. However, I still don't really understand why they chose $q$ to be $u^3+v^3$ but maybe I'm just tired. February 1st, 2018, 07:09 PM #3 Global Moderator   Joined: Dec 2006 Posts: 20,919 Thanks: 2202 That's a reasonable question. Somehow, they had reason to believe that would be a good strategy. Thanks from ProofOfALifetime February 1st, 2018, 08:49 PM   #4
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Quote:
 Originally Posted by ProofOfALifetime I am just wondering how they went from equation (3) to the pair of equations $3uv+p=0$ and $u^3+v^3=q$. I understand if those are true then the original equation will be true, but I was wondering why they chose $3uv+p=0$ instead of $u+v=0$. Why did they set $u^3+v^3$ equal to $q$? This step just seems mysterious to me.
To see where this choice comes from, look at the book "Analysis by its history" by Wanne and Hairer. They explain in the first chapter where these choices come from. February 2nd, 2018, 10:51 AM #5 Senior Member   Joined: Oct 2016 From: Arizona Posts: 209 Thanks: 37 Math Focus: I'm still deciding, but my recent focus has been olympiad problems and math journal problems. This reminds me of a topic I was searching for on the internet; the difference between competition math and research math. Lately, I've been practicing a lot of problems from math competitions, and it sort of puts you in this habit of looking at math and asking to yourself, what am I "supposed" to do? You begin to think that every math problem has a path that you are supposed to take. But, I realize that research math is not like this. When I first read this proof, my thought was, how did he know that that was what he was "supposed to do"? But, in research math there is no "supposed to do". Anyways, thank you both for your responses Thanks from Joppy February 2nd, 2018, 10:52 AM   #6
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From: Arizona

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Math Focus: I'm still deciding, but my recent focus has been olympiad problems and math journal problems.
Quote:
 Originally Posted by Micrm@ss To see where this choice comes from, look at the book "Analysis by its history" by Wanne and Hairer. They explain in the first chapter where these choices come from.
Thank you. I will check it out! I love Springer math books! Tags equations Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Ismael Calculus 2 August 23rd, 2014 05:27 PM Ismael Calculus 0 August 23rd, 2014 03:56 PM ZeusTheMunja Linear Algebra 20 January 25th, 2013 05:52 AM maximade Calculus 4 June 15th, 2010 07:37 PM cafegurl Algebra 6 August 3rd, 2009 07:58 AM

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