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February 27th, 2017, 03:36 PM  #1 
Newbie Joined: Feb 2017 From: Maryland Posts: 3 Thanks: 0  Can someone help me get started on this proof?
Let f be analytic and bounded by M in z≤ r. Prove that f (n)(z) ≤ n!M/〖(rz)〗^n for (z < r).

February 27th, 2017, 03:50 PM  #2 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,091 Thanks: 2360 Math Focus: Mainly analysis and algebra 
I can't decipher your question.

February 27th, 2017, 04:00 PM  #3 
Senior Member Joined: Aug 2012 Posts: 1,661 Thanks: 427  That expression does not look right. What is $n$? Do you by any chance mean $f^n(z)$? Or $f^{(n)}(z)$ meaning the $n$th derivative? Also in my opinion and speaking only for myself, questions at this level should certainly be $\LaTeX$'d. If you can hack complex variables you can certainly hack $\LaTeX$ Last edited by Maschke; February 27th, 2017 at 04:03 PM. 
February 27th, 2017, 07:05 PM  #4 
Senior Member Joined: Aug 2012 Posts: 1,661 Thanks: 427 
ps  I hope I didn't frighten off the OP. It's ok if you don't use math markup. But what you wrote is not correct as given.


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