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 February 27th, 2017, 02:36 PM #1 Newbie   Joined: Feb 2017 From: Maryland Posts: 3 Thanks: 0 Can someone help me get started on this proof? Let f be analytic and bounded by M in |z|≤ r. Prove that |f (n)(z)| ≤ n!M/〖(r-|z|)〗^n for (|z| < r).
 February 27th, 2017, 02:50 PM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,330 Thanks: 2457 Math Focus: Mainly analysis and algebra I can't decipher your question.
February 27th, 2017, 03:00 PM   #3
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Quote:
 Originally Posted by FournierDaniel |f (n)(z)|
That expression does not look right. What is $n$? Do you by any chance mean $f^n(z)$? Or $f^{(n)}(z)$ meaning the $n$-th derivative?

Also in my opinion and speaking only for myself, questions at this level should certainly be $\LaTeX$'d. If you can hack complex variables you can certainly hack $\LaTeX$

Last edited by Maschke; February 27th, 2017 at 03:03 PM.

 February 27th, 2017, 06:05 PM #4 Senior Member   Joined: Aug 2012 Posts: 1,956 Thanks: 547 ps - I hope I didn't frighten off the OP. It's ok if you don't use math markup. But what you wrote is not correct as given.

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