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February 27th, 2017, 04:24 AM  #1 
Newbie Joined: Dec 2015 From: England Posts: 27 Thanks: 0  putting in form z=x+iy
Please could some one help with how to put this equation into the form x+iy=z as I am stuck

February 27th, 2017, 05:04 AM  #2 
Senior Member Joined: Sep 2015 From: CA Posts: 1,304 Thanks: 669 
$z^2 + 2z  i \sqrt{3} = 0$ complete the square $(z+1)^2  1  i\sqrt{3} = 0$ $(z+1)^2 = 1+i\sqrt{3}$ $z+1 = \pm \sqrt{1+i\sqrt{3}}$ $z = 1 \pm \sqrt{1+i\sqrt{3}}$ Now we need to deal with the radical. $1+i\sqrt{3} = 2e^{i\pi/3}$ $\sqrt{1+i\sqrt{3}} = \sqrt{2}e^{i\pi/6} = \sqrt{\dfrac 3 2 }+\dfrac{i}{\sqrt{2}}$ so $z = 1 + \sqrt{\dfrac 3 2 }+\dfrac{i}{\sqrt{2}}$ $z = 1  \sqrt{\dfrac 3 2 }\dfrac{i}{\sqrt{2}}$ 

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