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 January 22nd, 2013, 05:31 AM #1 Newbie   Joined: Aug 2012 Posts: 8 Thanks: 0 Is this proof valid Let: x,u,y,v:C?R be functions in the complex variable s=a+ib defined by convergente series. I have this implication: If x(s)=u(s),y(s)=v(s) , then after some steps on these series one get an equation of the form: h(s)=0 which give one value of s as s=1+ib for some b . I call this result (s=1+ib ) as "(P)". The function h here depends on the given functions x,u,y,v . Its formula is not important. let A=s?C (s)=u(s),y(s)=v(s) and B=s?C (s)=u(s)=y(s)=v(s)=0 is a proper subset of A . I know that if s?A then (P) holds true. My question is as follow: What happen if s?B . Is (P) true or false!. We remark here that if s?B then we cannot construct the function h and hence we cannot deduce (P), i.e., if x(s)=u(s)=y(s)=v(s)=0 then I cannot do anything and the proof stoped here. January 22nd, 2013, 01:51 PM #2 Global Moderator   Joined: May 2007 Posts: 6,856 Thanks: 745 Re: Is this proof valid I'll start by saying I have no idea what you are trying to do. However you say that something is true for (all?) s in A. Since B is a subset of A, it will be true for s in B. January 28th, 2013, 03:37 AM #3 Senior Member   Joined: Dec 2012 Posts: 148 Thanks: 0 Re: Is this proof valid could you post original version of problem??? Tags proof, valid Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post eddybob123 Number Theory 2 August 1st, 2013 10:21 PM rummi Real Analysis 1 November 21st, 2012 08:19 PM rummi Real Analysis 1 October 5th, 2012 01:11 PM rummi Calculus 3 September 26th, 2012 03:54 PM ElMarsh Algebra 4 September 19th, 2009 06:05 AM

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