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December 13th, 2012, 11:21 AM   #1
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modulus of complex numbers

Hi! I I'm having problems with the calculation of these two examples. (see attachment)

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 December 14th, 2012, 03:00 AM #2 Senior Member   Joined: May 2011 Posts: 501 Thanks: 6 Re: modulus of complex numbers For the first one, you are finding a closed form for $\sum_{k=1}^{n}(3k-2)$ $3\sum_{k=1}^{n}k-2\sum_{k=1}^{n}1$ Now, just use the closed form for the sum of the integers: $\sum_{k=1}^{n}k=\frac{n(n+1)}{2}$ and $\sum_{k=1}^{n}1=n$, then put it together. For the second one, I am having a difficult time reading the denominator in the middle term. Is that 3+2i?. If so, just reduce it down. You should get $9-13i$. What is the modulus of this?.

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