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February 10th, 2008, 08:34 AM   #1
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Complex number circle

|z-2+i|=3

That is circle, but I'm stuck with it. Can't draw it on the paper.
Little help is much appreciated.
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February 10th, 2008, 10:28 AM   #2
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Re: Complex number circle

Quote:
Originally Posted by t031
|z-2+i|=3

That is circle, but I'm stuck with it. Can't draw it on the paper.
Little help is much appreciated.
z=x+yi

|x+yi-2+1|=3
|x-2+(y+1)i|=3
|z|=sqrt(x^2+y^2)
In this case x=x-2 and y=y+1 so

sqrt((x-2)^2+(y+1)^2)=3 /^2
(x-2)^2+(y+1)^2=3^2

Circle (x-p)^2+(y-q)^2=r^2
Center of the circle is S(p,q) and r is the radius.

I think you will now be able to draw it.
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February 10th, 2008, 12:48 PM   #3
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Re: Complex number circle

Quote:
Originally Posted by t031
|z-2+i|=3

That is circle, but I'm stuck with it. Can't draw it on the paper.
Little help is much appreciated.
The center is at 2-i and the radius is 3.
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February 10th, 2008, 09:13 PM   #4
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