November 7th, 2011, 03:35 AM  #1 
Newbie Joined: Jul 2009 Posts: 9 Thanks: 0  a rectifiable path Let f(t) = exp( (1+i )(t^1) ) for 0< t <=1 and f(0)=0 show that f is a rectifiable path . " sorry for not using latex " 
November 7th, 2011, 04:19 AM  #2 
Math Team Joined: Nov 2010 From: Greece, Thessaloniki Posts: 1,990 Thanks: 133 Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus  Re: a rectifiable path [color=#000000]Compute, .[/color] 
November 8th, 2011, 10:51 AM  #3 
Newbie Joined: Jul 2009 Posts: 9 Thanks: 0  Re: a rectifiable path Thank you Zardoz for your answer , ^__^ But how can i show that f(t) is of bounded variation 
November 8th, 2011, 02:27 PM  #4 
Math Team Joined: Nov 2010 From: Greece, Thessaloniki Posts: 1,990 Thanks: 133 Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus  Re: a rectifiable path [color=#000000]You have, so .[/color] 

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