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 October 18th, 2010, 02:13 PM #1 Member   Joined: Apr 2010 Posts: 91 Thanks: 0 Finding real number in complex number Find real numbers x, y such that $(1 - 3i)x + (2 + 5i)y= 2i$ I dont know what to do.
October 18th, 2010, 04:38 PM   #2
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Re: Finding real number in complex number

Quote:
 Originally Posted by TsAmE Find real numbers x, y such that $(1 - 3i)x + (2 + 5i)y= 2i$ I dont know what to do.
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x -3x*i + 2y + 5y*i = 2i
Group real and imaginary parts

(x + 2y) + (-3x + 5y)i = 0 + 2i.
Notice that I added the "0" on the right side.

The real part on the left is x + 2y. We equate that to the real part on the right side = 0
So x + 2y = 0.
Similarly, we equate imaginary parts.

-3x + 5y = 2

Solve the system of equations!

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