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June 12th, 2018, 02:27 AM   #1
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Work out how much volume is required

A solution containing diclofenac sodium (MW 381.1 g/mol) at a concentration of 79.5mg/100mL in buffer was prepared. What volume of the solution was required in order to carry out a microsomal incubation containing 25µM of the drug in 1mL?

I think we have to use (C1)(V1) = (C2)(V2)

Calculating C1:
79.5mg/100mL = 0.795g/L
(0.795g/L)/(381.1g/mol)=0.00209mol/L

Calculating C2:
25microM = 0.000025mol/L

V1 = [(C2)(V2)] / C1
V1 = [(0.000025)(1)] / (0.00209)
V1 = 0.0120mL

is that correct?
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June 12th, 2018, 11:52 AM   #2
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Quote:
Originally Posted by mathmathy View Post
A solution containing diclofenac sodium (MW 381.1 g/mol) at a concentration of 79.5mg/100mL in buffer was prepared. What volume of the solution was required in order to carry out a microsomal incubation containing 25µM of the drug in 1mL?

I think we have to use (C1)(V1) = (C2)(V2)

Calculating C1:
79.5mg/100mL = 0.795g/L
(0.795g/L)/(381.1g/mol)=0.00209mol/L

Calculating C2:
25microM = 0.000025mol/L

V1 = [(C2)(V2)] / C1
V1 = [(0.000025)(1)] / (0.00209)
V1 = 0.0120mL

is that correct?
I don't think so, but perhaps I am not reading the question correctly.

As I see it, you are find the volume of the stock solution which contains 25 micromoles of diclofenac and make it up to 1ml.

The concentration of diclofenac will then be 25 uM/ml. But this is not the concentration of the stock solution.

Last edited by skipjack; June 12th, 2018 at 10:02 PM.
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June 12th, 2018, 07:24 PM   #3
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But isn't 25uM = 25umol/L
so that is a concentration in itself?
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