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December 3rd, 2016, 12:18 PM   #1
Joined: Sep 2016
From: zambia

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Empirical formula

I need help with the following question. I don't know where I am making a mistake in the calculations. The answer I am getting is C3H4O4 which is wrong

The numbers in the formula CHO are subscripts.


A compound contains carbon, hydrogen and oxygen. Combustion of 10.68 mg of the compound yields 16.01 mg of carbon dioxide and 4.37 of water. The molar mass of the compound is 176.1 g/mol. What is the empirical formula of the compound?

Last edited by skipjack; December 3rd, 2016 at 12:25 PM.
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December 3rd, 2016, 01:29 PM   #2
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Suppose the combustion reaction is $\text{C}_6\text{H}_8\text{O}_6 + 5\text{O}_2 = 6\text{CO}_2 + 4\text{H}_2\text{O}$... the description doesn't clarify whether that extra oxygen is allowed, but I'm assuming that it is.
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