
Calculus Calculus Math Forum 
 LinkBack  Thread Tools  Display Modes 
November 11th, 2009, 09:34 PM  #1 
Newbie Joined: Oct 2009 Posts: 7 Thanks: 0  Please Help me To Findout the Parameter if this circle equation number 1 is given equation equation number 2 is formula please solve this equation answer should be 2(pi)a 
November 11th, 2009, 11:55 PM  #2 
Newbie Joined: Nov 2009 Posts: 1 Thanks: 0  Re: Please Help me To Findout the Parameter if this circle
The diagram given gives me the impression that the center of the circle is at (0,0). This leads me to assume that equation number 1 is the equation of the circle. Thus the circle has radius a. The parameter/circumfrence of the circle is always 2(pi)r or (pi)d, if the radius is a then the parameter is 2(pi)a as required. Hope it helped 
November 12th, 2009, 12:23 AM  #3 
Newbie Joined: Oct 2009 Posts: 7 Thanks: 0  Re: Please Help me To Findout the Parameter if this circle
yes u know this thing but my question is how to solve this prob

November 12th, 2009, 03:40 AM  #4 
Senior Member Joined: Mar 2009 Posts: 318 Thanks: 0 
You've posted a picture and two equations. What, exactly, is the "question"? Please be complete. Thank you! 
November 12th, 2009, 07:50 AM  #5 
Newbie Joined: Oct 2009 Posts: 7 Thanks: 0  Re: Please Help me To Findout the Parameter if this circle
i want to findout entire circle length by this forum. by using equation number 2

November 12th, 2009, 04:34 PM  #6 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,923 Thanks: 1123 Math Focus: Elementary mathematics and beyond  Re: Please Help me To Findout the Parameter if this circle
We'll integrate from to (so is positive) and multiply by 4 to get the circle's circumference. See this: Trigonometric substitution 

Tags 
circle, findout, parameter 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
function with parameter  Arnhus  Calculus  11  March 31st, 2014 12:36 PM 
what is parameter?  helloprajna  Number Theory  6  July 9th, 2013 09:46 PM 
Integral with a parameter  OriaG  Calculus  3  August 24th, 2012 12:01 PM 
eliminate the parameter  1love  Calculus  5  May 22nd, 2012 09:51 PM 
parameter integral  DeliaDS  Calculus  1  June 20th, 2010 07:03 AM 