- **Calculus**
(*http://mymathforum.com/calculus/*)

- - **Area bounded between 2 curves**
(*http://mymathforum.com/calculus/9475-area-bounded-between-2-curves.html*)

Area bounded between 2 curvesConsider the area bounded between curves y=-2x and y=3-x^{2}. If 2 vertical lines that are a unit apart intersect this certain bounded area, where should they be placed so that they contain the most amount of the area between them? What's the max. area? I keep getting told that this is the rule I am supposed to use: But I am unsure of how to apply the rule here. Ok so the latex isn't working ... int a - b (-2x - 3-x^2) dx But then how to proceed? |

Re: Area bounded between 2 curvesHello, Civilization! Quote:
The graph looks like this: Code: ` |` [color=beige]. . [/color] But check my work . . . please! |

Re: Area bounded between 2 curvesWhoa, very nice diagram. :D I actually stopped looking at your post once you typed in (3-x^2 etc.) in the integral from a to a+1. It was easy for me to figure out what the A equals to after having the equation written. Do you have any tips on how to actually start an integration problem like this? Obviously on a test I won't have any help. :D After getting the right integrand, integration becomes easier. Anyway, A' = 1-2a 2a = 1 a = 1/2 So the lines should be placed at x = 1/2 and x = 3/2, right? |

All times are GMT -8. The time now is 12:12 AM. |

Copyright © 2019 My Math Forum. All rights reserved.