My Math Forum A problem about speed and distance

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 October 27th, 2009, 01:58 PM #1 Newbie   Joined: Oct 2009 Posts: 3 Thanks: 0 A problem about speed and distance A car traveling at 45 miles per hour is brought to a stop, at constant deceleration, 198 feet from where the brakes are applied. (Give your answers correct to the nearest whole number.) (a) How far has the car moved when its speed has been reduced to 30 miles per hour? ___ ft (b) How far has the car moved when its speed has been reduced to 15 miles per hour? ___ft From here i understand that turn 45 mi into feet so i get 23760 ft 30miles = 158400ft 15miles= 79200ft V^2= Vo^2 +2a [delta (s)] V^2= (0) + 2(23760ft) (198ft) V=3067 so insted of the 23760 do i plug in 15 miles(turned into feet) and 30miles?

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### a car traveling at 45 miles per hour is brought to a stop at constant deceleration

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