My Math Forum Reversing the order of Integration

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 October 16th, 2009, 08:23 AM #1 Newbie   Joined: Oct 2009 Posts: 27 Thanks: 0 Reversing the order of Integration For the following double integral, sketch the region of integration and write the equivalent double integral with the order of integration reversed. $\int\int \sqrt{x^2+y^2} dA$ After sketching it looked like a small triangle dont know how to upload some kind of drawing but the reversed integral I got was: $\int_0^1 \int_0^{\sqrt{y}} dy dx$ is this reversed integral correct with the right bounds?
 October 16th, 2009, 08:45 AM #2 Senior Member   Joined: Dec 2008 Posts: 251 Thanks: 0 Re: Reversing the order of Integration What is the region of integration? In the reversed integral, $y$ cannot occur in a limit of an integral with respect to $y$, as is the case in $\int\,_0^1\int\,_0^{\sqrt{y}}\,dy\,dx.\mbox{ (Incorrect)}$
 October 16th, 2009, 12:46 PM #3 Newbie   Joined: Oct 2009 Posts: 27 Thanks: 0 Re: Reversing the order of Integration region was in the first quadrant. what would the right answer be?
October 16th, 2009, 01:47 PM   #4
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Re: Reversing the order of Integration

Quote:
 Originally Posted by OSearcy4 region was in the first quadrant. what would the right answer be?
You need to be more more specific. There are lots of different regions in the first quadrant.

 October 17th, 2009, 03:32 PM #5 Newbie   Joined: Oct 2009 Posts: 27 Thanks: 0 Re: Reversing the order of Integration this is all i was given for the question.

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