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 June 9th, 2009, 07:44 PM #1 Member   Joined: May 2009 Posts: 58 Thanks: 0 A Cylindrical hole A Cylindrical hole is drilled through the center of a sphere of radius R. Use the method of cylindrical shells to find the volume of the remaining solid, given that the solid is 6 cm high. Answer : V = 4? ? x ?(R² - x²) dx ..... from ?(R² - (3)²) to R = -4?/3 (R² - x²)^(3/2) ..... from ?(R² - (3)²) to R = 36 ? Are these correct? Thank you
 June 9th, 2009, 08:05 PM #2 Senior Member   Joined: Dec 2008 Posts: 251 Thanks: 0 Re: A Cylindrical hole Your answer looks correct, and I again apologize for another mistake in which I claimed that $\sqrt{R^2\,-\,r^2}\,=\,6\,\mbox{cm}$.
 June 10th, 2009, 03:57 PM #3 Global Moderator   Joined: Dec 2006 Posts: 18,586 Thanks: 1489 $36\pi\text{ cm}^{\small{3}}$

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