Calculus Calculus Math Forum

 July 14th, 2015, 01:13 PM #1 Member   Joined: Sep 2013 Posts: 58 Thanks: 0 Gradient Question So I don't get what I did wrong either. fx(1.3)=-6x=-6(1)=-6 fy(1,3)=-6y=-6(3)=-18 Gradiant <-6,-18> Length is Sqrt((-6)^2+(-1 ^2)=Sqrt(360). Unit Vector =1/sqrt(360)<-6,-18> b) I'm not sure if we find the Length of the Gradiant Vector of length of the Unit Gradiant Vector Gradiant <-6,-18> Length of Gradiant: Sqrt(360) What am I doing wrong? --------------------------------------------------------------------------------------------------------------  July 14th, 2015, 02:18 PM #2 Member   Joined: Sep 2013 Posts: 58 Thanks: 0 Nevermind. The question asks for the fastest descent (slope is negative), while the gradient always gives the fastest ascent (where the slope is positive. I needed to multiple the vector<-6,-8> by negative one to get to a unit vector of 1/sqrt(360)<6,18> and hence a fastest downward speed of -sqrt(360). Sorry for the trouble. You can close the thread. From, Tzad Tags gradient, question Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post coachcft Calculus 2 December 15th, 2012 01:25 PM truthseeker Linear Algebra 12 October 2nd, 2012 08:07 AM veronicak5678 Real Analysis 0 May 6th, 2012 10:08 AM Weijingren Calculus 1 January 20th, 2009 03:20 AM dthomas86 Algebra 3 December 31st, 1969 04:00 PM

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