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Gradient QuestionSo I don't get what I did wrong either. fx(1.3)=-6x=-6(1)=-6 fy(1,3)=-6y=-6(3)=-18 Gradiant <-6,-18> Length is Sqrt((-6)^2+(-18)^2)=Sqrt(360). Unit Vector =1/sqrt(360)<-6,-18> b) I'm not sure if we find the Length of the Gradiant Vector of length of the Unit Gradiant Vector Gradiant <-6,-18> Length of Gradiant: Sqrt(360) What am I doing wrong? -------------------------------------------------------------------------------------------------------------- http://i.imgur.com/i4jqXq8.png |

Nevermind. The question asks for the fastest descent (slope is negative), while the gradient always gives the fastest ascent (where the slope is positive. I needed to multiple the vector<-6,-8> by negative one to get to a unit vector of 1/sqrt(360)<6,18> and hence a fastest downward speed of -sqrt(360).Sorry for the trouble. You can close the thread. From, Tzad |

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