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 May 27th, 2009, 01:34 PM #1 Newbie   Joined: May 2009 Posts: 1 Thanks: 0 I need help I am teaching myself What is the limit of (X^-3)*ln(abs x) as x approaches 0?.... abs is absolute value.
May 27th, 2009, 01:46 PM   #2
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Re: I need help I am teaching myself

Quote:
 Originally Posted by chrisdg What is the limit of (X^-3)*ln(abs x) as x approaches 0?.... abs is absolute value.
x^-3 -> + or -oo as x->0.

ln(|x|) -> -oo as x->0.

Net result, you have a sign ambiguity.

 May 27th, 2009, 03:55 PM #3 Senior Member   Joined: Jul 2008 Posts: 895 Thanks: 0 Re: I need help I am teaching myself Graph the function, and you'll see how it behaves as x approaches zero from the negative and from the positive.

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