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May 27th, 2009, 01:34 PM   #1
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I need help I am teaching myself

What is the limit of (X^-3)*ln(abs x) as x approaches 0?.... abs is absolute value.
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May 27th, 2009, 01:46 PM   #2
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Re: I need help I am teaching myself

Quote:
Originally Posted by chrisdg
What is the limit of (X^-3)*ln(abs x) as x approaches 0?.... abs is absolute value.
x^-3 -> + or -oo as x->0.

ln(|x|) -> -oo as x->0.

Net result, you have a sign ambiguity.
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May 27th, 2009, 03:55 PM   #3
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Re: I need help I am teaching myself

Graph the function, and you'll see how it behaves as x approaches zero from the negative and from the positive.
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