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March 19th, 2009, 01:58 AM   #1
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Solving for indefinite integral

My daughter at college asked me to help her with these but it's been years since I've done them. I said I would try and then look over what she comes up with so any help would be great not so I can give her the answers but so I can tell her whether or not she on the right track and help her try to find it!

Problem 1
?(t^3/2 + 2t^1/2 -4t^-1/2)dt=
?t^3/2(dt) + 2?t^1/2(dt) -4?t^-1/2(dt)=
2/3t^5/2 +(2)(2)t^3/2 -(4)(2)t^1/2 +c=
2/3t^5/2+4t^3/2-8t^1/2+c

Am I anywhere near right with this one?

And the second one is:
?sqrt(t)(t^2+t-1)dt
but I have no idea where to go with it...

Thanks to any and all that help and for any help you can give.
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March 19th, 2009, 02:48 AM   #2
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Re: Solving for indefinite integral

Quote:
Originally Posted by 4littlepiggiesmom
Problem 1
?(t^3/2 + 2t^1/2 -4t^-1/2)dt=
?t^3/2(dt) + 2?t^1/2(dt) -4?t^-1/2(dt)=
2/3t^5/2 +(2)(2)t^3/2 -(4)(2)t^1/2 +c=
2/3t^5/2+4t^3/2-8t^1/2+c

And the second one is:
?sqrt(t)(t^2+t-1)dt
Problem 1

Break it up into three separate integrals and factor out the constants.



Use where n is the original exponent then multiply by the constant outside of the integral to get:




the second one
(when multiplying add the exponents)



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March 19th, 2009, 05:20 AM   #3
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Re: Solving for indefinite integral

Thank you I knew after working some more I had to add on the second one but wasn't sure where it fit in!
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