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March 18th, 2009, 02:57 PM   #1
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Double integral 16dA, limits defined by circle

How do I solve this double integral?

where S1 is the circle
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March 18th, 2009, 08:25 PM   #2
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Change to polar coordinates.
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November 8th, 2016, 06:09 AM   #3
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Originally Posted by ;23464
How do I solve this double integral?

where S1 is the circle
This is just $\displaystyle 16\int_S\int dA$ which is just 16A: 16 times the area of S.

What is the area of a circle with radius 3?
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November 8th, 2016, 08:55 AM   #4
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Frankly, I think OP is asking for more than the area of a circle. Without constant 16

$\displaystyle \int dA = \int_{0}^{2\pi}\int_{0}^{R}rdrd\theta=\int_{0}^{2\ pi}\frac{R^{2}}{2}d\theta=\pi R^{2}$

and R =3

Last edited by zylo; November 8th, 2016 at 09:19 AM. Reason: R=3
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