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March 18th, 2009, 02:57 PM  #1 
Newbie Joined: Mar 2009 Posts: 9 Thanks: 0  Double integral 16dA, limits defined by circle
How do I solve this double integral? where S1 is the circle 
March 18th, 2009, 08:25 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,634 Thanks: 2080 
Change to polar coordinates.

November 8th, 2016, 06:09 AM  #3  
Math Team Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902  Quote:
What is the area of a circle with radius 3?  
November 8th, 2016, 08:55 AM  #4 
Banned Camp Joined: Mar 2015 From: New Jersey Posts: 1,720 Thanks: 125 
Frankly, I think OP is asking for more than the area of a circle. Without constant 16 $\displaystyle \int dA = \int_{0}^{2\pi}\int_{0}^{R}rdrd\theta=\int_{0}^{2\ pi}\frac{R^{2}}{2}d\theta=\pi R^{2}$ and R =3 Last edited by zylo; November 8th, 2016 at 09:19 AM. Reason: R=3 

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16da, circle, defined, double, integral, limits 
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