My Math Forum Double integral 16dA, limits defined by circle

 Calculus Calculus Math Forum

 March 18th, 2009, 03:57 PM #1 Newbie   Joined: Mar 2009 Posts: 9 Thanks: 0 Double integral 16dA, limits defined by circle How do I solve this double integral? $\int \int_{S1} \16dA$ where S1 is the circle $(x,y)\ |\ x^2+y^2 \le 9$
 March 18th, 2009, 09:25 PM #2 Global Moderator   Joined: Dec 2006 Posts: 19,888 Thanks: 1836 Change to polar coordinates.
November 8th, 2016, 07:09 AM   #3
Math Team

Joined: Jan 2015
From: Alabama

Posts: 3,261
Thanks: 894

Quote:
 Originally Posted by ;23464 How do I solve this double integral? $\int \int_{S1} 16dA$ where S1 is the circle $(x,y)\ |\ x^2+y^2 \le 9$
This is just $\displaystyle 16\int_S\int dA$ which is just 16A: 16 times the area of S.

What is the area of a circle with radius 3?

 November 8th, 2016, 09:55 AM #4 Senior Member   Joined: Mar 2015 From: New Jersey Posts: 1,603 Thanks: 115 Frankly, I think OP is asking for more than the area of a circle. Without constant 16 $\displaystyle \int dA = \int_{0}^{2\pi}\int_{0}^{R}rdrd\theta=\int_{0}^{2\ pi}\frac{R^{2}}{2}d\theta=\pi R^{2}$ and R =3 Last edited by zylo; November 8th, 2016 at 10:19 AM. Reason: R=3

 Tags 16da, circle, defined, double, integral, limits

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post MasterOfDisaster Calculus 0 February 3rd, 2013 09:53 PM ballensr Algebra 0 February 9th, 2012 10:51 AM maximus101 Calculus 1 February 21st, 2011 07:31 AM nadroj Calculus 4 February 9th, 2010 05:12 PM Jamers328 Advanced Statistics 2 January 12th, 2009 04:44 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top