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March 16th, 2009, 04:20 AM | #1 |
Newbie Joined: Mar 2009 Posts: 20 Thanks: 0 | Domains and composites.
Hi, For the function For the functions f.h = h.f = which would then result in both being |
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March 16th, 2009, 09:59 AM | #2 |
Newbie Joined: Mar 2009 Posts: 21 Thanks: 0 | Re: Domains and composites.
For the first function, the domain would be For the second problem: |
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March 16th, 2009, 03:22 PM | #3 |
Newbie Joined: Mar 2009 Posts: 20 Thanks: 0 | Re: Domains and composites.
Not -11? Also, how did you get the first of the composites? |
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March 16th, 2009, 06:25 PM | #4 |
Senior Member Joined: Feb 2009 From: Adelaide, Australia Posts: 1,519 Thanks: 3 | Re: Domains and composites.
Yes, -11. For h of f: first you square, then take the (positive) square root. Zero goes to zero, positive x goes to x, negative x goes to -x (which is positive). For f of h: first you take the square root, then square. Zero goes to zero, positive x goes to x, negative x has no square root and so can't be in the domain. The codomain for both is all non-negative real numbers. |
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March 16th, 2009, 07:41 PM | #5 |
Senior Member Joined: Dec 2008 Posts: 306 Thanks: 0 | Re: Domains and composites.
Aswoods, you mean the range! You don't get to specify the codomain.
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March 17th, 2009, 05:23 AM | #6 |
Newbie Joined: Mar 2009 Posts: 21 Thanks: 0 | Re: Domains and composites.
Good ol' codomain/range war =]
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