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 March 23rd, 2015, 09:21 PM #1 Newbie   Joined: Mar 2015 From: Munich Posts: 4 Thanks: 0 What is the shape of the graph? Hi guys, I still can not solve the following functions and needed help. Wanted is the following function, which is on the course of a closed, convex function graph. The function graph is a set of equally long distances, with seam-free merges intervals of time together. Per "time interval (1 sec.)" Is the distance s traversed. The distance s can be curved on the course. Curvature: Degree / time [° / s]; for example, by 2 [° / s], or by 2 * s [° / s], or even to 0 [° / s] (no curvature) Table of curvature per time interval. Time[s] curvature degree/time [°/s] 1________________ {0*s [°/s]} 2________________ {0*s [°/s]} 3________________ {0*s [°/s]} 4________________ {1*s [°/s]} 5________________ {0*s [°/s]} 6________________ {2*s [°/s]} 7________________ {0*s [°/s]} 8________________ {2*s [°/s]} 9________________ {1*s [°/s]} 10________________{2*s [°/s]} 11________________{0*s [°/s]} 12________________{4*s [°/s]} 13________________{0*s [°/s]} From this table, a function equation will now be created with the corresponding function graph given above. Function graph: - Closed seam loosely continuous, - Convex> Links curvature (positive) f '' (x)> 0; Function graph counterclockwise Curvature behavior of a function: differential calculus 2nd derivative I would be happy with simple words to get a detailed explanation, easy to understand. Best greetings March 24th, 2015, 08:18 AM #2 Newbie   Joined: Mar 2015 From: Munich Posts: 4 Thanks: 0 Good Morning, please help me, I can not imagine that the problem is too hard for you ?! If the task should be somewhat unclear, please ask me! The function graph passes through the "distance s“ pro “time interval (1 sec.)". "Distance s“ is a positive number. Function graph "closed" means that the start point and end point of the graph are the same. I be happy if they could help me to the solution. March 24th, 2015, 03:53 PM #3 Global Moderator   Joined: Dec 2006 Posts: 20,835 Thanks: 2162 Your posts don't make sense, especially sentences such as "The distance s can be curved on the course." and phrases such as "seam-free merges". Explaining these examples wouldn't help much, as almost everything is equally incomprehensible. Thanks from MarkFL and Touch8me March 24th, 2015, 07:31 PM #4 Newbie   Joined: Mar 2015 From: Munich Posts: 4 Thanks: 0 Thanks for the reply, I'm sorry if I can not describe the mathematical problem. Then please help me with this. Wanted is a closed (start point and end point are the same), convexer functiongraph (Convex> Links curvature (positive) f '' (x)> 0; counterclockwisedirection). This functiongraph consists of 13 distances (13 seconds time duration) with the length s. In the 13 timeintervals is each distance s curved (curvature: deg/Time [°/s]), for example to 2*s [°/s], or no curvature (Distance s is smooth) is 0 [°/s] or 0*s [°/s]. Example of the degree [°] a curvature of a distance s is "2*s [°]" or "0 [°]" or "0*s [°]". Table of the curvature of distance s per time interval. Time [s] ______curvature degree / time [°/s] 1________________ {0*s [°/s]} ___ no curvature 2________________ {0*s [°/s]} ___ no curvature 3________________ {0*s [°/s]} ___ no curvature 4________________ {1*s [°/s]} 5________________ {0*s [°/s]} ___ no curvature 6________________ {2*s [°/s]} 7________________ {0*s [°/s]} ___ no curvature 8________________ {2*s [°/s]} 9________________ {1*s [°/s]} 10 _______________{2*s [°/s]} 11 _______________{0*s [°/s]} ___ no curvature 12 _______________{4*s [°/s]} 13 _______________{0*s [°/s]} ___ no curvature From this table, is a function equation can be created with the corresponding function graph. I hope that now has become a lot clearer when the task should be somewhat unclear, please ask me! Last edited by Touch8me; March 24th, 2015 at 07:40 PM. March 26th, 2015, 05:15 PM #5 Newbie   Joined: Mar 2015 From: Munich Posts: 4 Thanks: 0 Good Evening, Nobody has an idea for a solution to a functional equation ?! Why is this problem so difficult to understand? I do not know if it is important for the solution. I noticed that the curvature indices (factors) from the table (0; 0; 0; 1; 0; 2; 0; 2 1; 2; 0; 4; 0) the sequence of the "Proper divisor" corresponds. If you have questions about the statement of the problem, then please ask! Tags graph, shape Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post caters Geometry 2 March 20th, 2015 05:33 PM shunya Geometry 3 June 26th, 2014 07:56 PM maxgeo Algebra 6 December 30th, 2012 09:59 PM computronium Real Analysis 4 June 27th, 2009 06:39 AM maxgeo Abstract Algebra 1 December 31st, 1969 04:00 PM

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