My Math Forum New Method for Solving Polynomial Equations (Part A - Quadratic Equations)

 Calculus Calculus Math Forum

 August 23rd, 2014, 04:52 PM #1 Newbie   Joined: Aug 2014 From: USA Posts: 10 Thanks: 1 New Method for Solving Polynomial Equations (Part A - Quadratic Equations) New Method for Solving Polynomial Equations (Part A - Quadratic Equations)
 August 23rd, 2014, 06:21 PM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,558 Thanks: 2558 Math Focus: Mainly analysis and algebra I've only watched this one so far, but I'm not blown away. The equation $$x = \frac{1}{2a} \left( -b \pm \sqrt{b^2 -4ac} \right)$$is not new and is basically what you have derived since your $X = \frac{b}{2a}$. Thanks from topsquark and Ismael
 August 23rd, 2014, 06:27 PM #3 Newbie   Joined: Aug 2014 From: USA Posts: 10 Thanks: 1 Thanks.. The above equation is derived from the one I mentioned. Go to http://theglobaljournals.com/ijsr/fi...4_0c336_45.pdf to see the whole new method not just for solving quadratic equations. This method is the fastest at all.. Thanks again..

 Tags equations, method, part, polynomial, quadratic, solving

### new method for solving math

Click on a term to search for related topics.
 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post TheMathNoob Algebra 7 March 19th, 2014 12:11 AM bilano99 Algebra 4 June 14th, 2012 09:38 AM bilano99 Algebra 4 June 13th, 2012 08:48 AM scn7th Algebra 0 April 19th, 2012 07:08 PM Pumpkin99 Algebra 4 November 10th, 2011 04:23 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top