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August 23rd, 2014, 03:52 PM  #1 
Newbie Joined: Aug 2014 From: USA Posts: 10 Thanks: 1  New Method for Solving Polynomial Equations (Part A  Quadratic Equations)
New Method for Solving Polynomial Equations (Part A  Quadratic Equations) 
August 23rd, 2014, 05:21 PM  #2 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,344 Thanks: 2466 Math Focus: Mainly analysis and algebra 
I've only watched this one so far, but I'm not blown away. The equation $$x = \frac{1}{2a} \left( b \pm \sqrt{b^2 4ac} \right)$$is not new and is basically what you have derived since your $X = \frac{b}{2a}$. 
August 23rd, 2014, 05:27 PM  #3 
Newbie Joined: Aug 2014 From: USA Posts: 10 Thanks: 1 
Thanks.. The above equation is derived from the one I mentioned. Go to http://theglobaljournals.com/ijsr/fi...4_0c336_45.pdf to see the whole new method not just for solving quadratic equations. This method is the fastest at all.. Thanks again.. 

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