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 August 16th, 2014, 06:18 PM #1 Newbie   Joined: Aug 2014 From: Belgium Posts: 1 Thanks: 0 Need help understanding something Hello, I need to find the pole points and zero points of the following equation GH= 3(p+2) / (p+8 )*(p²+8p+32) For zero points you get -2 and pole points are -8, -4+j4, -4-j4 (the p+2 in the numerator determines the zero points and the denominator determines the pole points) However, I can't figure out how you get those complex values. In order to get the pole points you need to have a p value, not p² (I think at least). So you'd have to convert it. J is a complex number -> sqroot of -1 Here is a screenshot of what I mean My current (flawed) theory is that you need to reduce p² to p by apply that p! rule, meaning you change (p²+8p+32) into (2p+8 ) -> 2(p+4) However, I can't figure out how you end up with the complex number out of this.
 August 17th, 2014, 02:24 PM #2 Global Moderator   Joined: May 2007 Posts: 6,641 Thanks: 625 The complex pole points are simply the roots of $p^2+8p+32=0$.

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