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August 16th, 2014, 06:18 PM   #1
Joined: Aug 2014
From: Belgium

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Need help understanding something


I need to find the pole points and zero points of the following equation GH= 3(p+2) / (p+8 )*(p²+8p+32)

For zero points you get -2 and pole points are -8, -4+j4, -4-j4 (the p+2 in the numerator determines the zero points and the denominator determines the pole points)

However, I can't figure out how you get those complex values.
In order to get the pole points you need to have a p value, not p² (I think at least). So you'd have to convert it.
J is a complex number -> sqroot of -1

Here is a screenshot of what I mean

My current (flawed) theory is that you need to reduce p² to p by apply that p! rule, meaning you change (p²+8p+32) into (2p+8 ) -> 2(p+4)
However, I can't figure out how you end up with the complex number out of this.
erpi is offline  
August 17th, 2014, 02:24 PM   #2
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The complex pole points are simply the roots of .
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