My Math Forum Inverse Laplace

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 July 21st, 2014, 03:17 AM #1 Newbie   Joined: Jul 2014 From: Am Posts: 1 Thanks: 0 Inverse Laplace Hello, is it good? IMG_0082.JPG - Speedy Share - upload your files here I dont wanna use complex numbers.
 July 24th, 2014, 03:01 PM #2 Math Team   Joined: Nov 2010 From: Greece, Thessaloniki Posts: 1,989 Thanks: 133 Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus According to the tables $\displaystyle\frac{1}{s^3-1}=\frac{-s-2}{3 \left(s^2+s+1\right)}+\frac{1}{3 (s-1)}$, $\displaystyle f(t)=\frac{1}{3} e^{-\frac{t}{2}} \left(e^{\frac{3 t}{2}}-\sqrt{3} \sin \left(\frac{\sqrt{3} t}{2}\right)-\cos \left(\frac{\sqrt{3} t}{2}\right)\right)$. Last edited by ZardoZ; July 24th, 2014 at 03:04 PM.

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