My Math Forum  

Go Back   My Math Forum > College Math Forum > Calculus

Calculus Calculus Math Forum


Reply
 
LinkBack Thread Tools Display Modes
July 21st, 2014, 04:17 AM   #1
Newbie
 
Joined: Jul 2014
From: Am

Posts: 1
Thanks: 0

Inverse Laplace

Hello, is it good?

IMG_0082.JPG - Speedy Share - upload your files here

I dont wanna use complex numbers.
tomecky is offline  
 
July 24th, 2014, 04:01 PM   #2
Math Team
 
Joined: Nov 2010
From: Greece, Thessaloniki

Posts: 1,989
Thanks: 133

Math Focus: pre pre pre pre pre pre pre pre pre pre pre pre calculus
According to the tables $\displaystyle\frac{1}{s^3-1}=\frac{-s-2}{3 \left(s^2+s+1\right)}+\frac{1}{3 (s-1)}$, $\displaystyle f(t)=\frac{1}{3} e^{-\frac{t}{2}} \left(e^{\frac{3 t}{2}}-\sqrt{3} \sin \left(\frac{\sqrt{3} t}{2}\right)-\cos \left(\frac{\sqrt{3} t}{2}\right)\right)$.

Last edited by ZardoZ; July 24th, 2014 at 04:04 PM.
ZardoZ is offline  
Reply

  My Math Forum > College Math Forum > Calculus

Tags
inverse, laplace



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
Inverse Laplace transform Asmir Complex Analysis 2 August 18th, 2013 06:49 AM
inverse laplace transform capea Complex Analysis 5 August 3rd, 2013 03:30 PM
Laplace tranform and inverse of Laplace transform Deiota Calculus 1 April 28th, 2013 11:28 AM
Inverse Laplace of: (1) / ( (1+s)^2 +1 ) = ? baylar10 Calculus 6 March 5th, 2013 11:13 AM
Inverse Laplace Transform timh Applied Math 1 June 7th, 2010 07:44 PM





Copyright © 2017 My Math Forum. All rights reserved.