May 7th, 2014, 09:24 PM  #1 
Newbie Joined: May 2014 From: India Posts: 12 Thanks: 0  differentiation 3
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May 8th, 2014, 05:36 AM  #2 
Senior Member Joined: Apr 2014 From: Greater London, England, UK Posts: 320 Thanks: 156 Math Focus: Abstract algebra 
If $x^2+y^2=a^2$ then $a=\pm\sqrt{x^2+y^2}$.

May 8th, 2014, 06:12 AM  #3 
Newbie Joined: May 2014 From: India Posts: 12 Thanks: 0  

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algebra, differentiation 
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