My Math Forum I am stuck on an integral problem.

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 April 5th, 2014, 03:43 PM #1 Newbie   Joined: Apr 2014 From: NY Posts: 3 Thanks: 0 I am stuck on an integral problem. I apologize for the sloppy writing. I don't understand where the first two in the final row of my solution comes from. I know how to solve the rest. I just need to know where the "2-" comes from. Thank you. P.S The final row should have the integral sign in the front.
 April 5th, 2014, 03:52 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,165 Thanks: 472 Math Focus: Calculus/ODEs Through your substitution, you have obtained: $\displaystyle \int\frac{2u}{u+1}\,du$ Now, suppose we add zero to the numerator of the integrand as follows: $\displaystyle \int\frac{2(u+1-1)}{u+1}\,du$ And then write it as: $\displaystyle \int\frac{2(u+1)-2}{u+1}\,du=\int 2-\frac{2}{u+1}\,du$ Thanks from CrimeAndPunishment

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