My Math Forum  

Go Back   My Math Forum > College Math Forum > Calculus

Calculus Calculus Math Forum

Thanks Tree1Thanks
  • 1 Post By MarkFL
LinkBack Thread Tools Display Modes
April 5th, 2014, 03:43 PM   #1
Joined: Apr 2014
From: NY

Posts: 3
Thanks: 0

I am stuck on an integral problem.

I apologize for the sloppy writing. I don't understand where the first two in the final row of my solution comes from. I know how to solve the rest. I just need to know where the "2-" comes from. Thank you.

P.S The final row should have the integral sign in the front.

CrimeAndPunishment is offline  
April 5th, 2014, 03:52 PM   #2
Senior Member
MarkFL's Avatar
Joined: Jul 2010
From: St. Augustine, FL., U.S.A.'s oldest city

Posts: 12,165
Thanks: 472

Math Focus: Calculus/ODEs
Through your substitution, you have obtained:

$\displaystyle \int\frac{2u}{u+1}\,du$

Now, suppose we add zero to the numerator of the integrand as follows:

$\displaystyle \int\frac{2(u+1-1)}{u+1}\,du$

And then write it as:

$\displaystyle \int\frac{2(u+1)-2}{u+1}\,du=\int 2-\frac{2}{u+1}\,du$
Thanks from CrimeAndPunishment
MarkFL is online now  

  My Math Forum > College Math Forum > Calculus

integral, problem, stuck

Thread Tools
Display Modes

Similar Threads
Thread Thread Starter Forum Replies Last Post
Stuck on an improper integral problem Christine Calculus 3 March 1st, 2013 08:56 AM
Stuck on this problem. sivela Calculus 1 February 19th, 2012 10:21 PM
stuck on a problem jordanshaw Calculus 3 October 6th, 2010 10:19 PM
Stuck on a problem INEEDHELP1 Calculus 1 September 30th, 2010 07:03 PM
stuck on problem adriana.alrb Algebra 5 August 30th, 2009 10:14 PM

Copyright © 2018 My Math Forum. All rights reserved.