My Math Forum improper integral

 Calculus Calculus Math Forum

 March 29th, 2014, 07:13 AM #1 Senior Member   Joined: Apr 2012 Posts: 135 Thanks: 1 improper integral i have the following integral: integral from -1 to pi/2 arcsinx/(x^2). The integral from -1 to 0 gives -oo and from 0 to pi/2 +oo... what is the conclusion here? Or integral from -1 to 1 1/x is this equal with 0? because we have the same amount of "infinity" on both sides. It is necessary to solve the other side of the improper integral if the first one is divergent? And the last question: It is possible to have -oo on one side , +oo on the other side and the integral to converge? Thank you! Thanks from zaidalyafey
 April 1st, 2014, 08:47 AM #2 Math Team     Joined: Aug 2012 From: Sana'a , Yemen Posts: 1,177 Thanks: 44 Math Focus: Theory of analytic functions $$\int^1_{-1} \frac{1}{x} \, dx \neq 0$$ because the integral actually diverges. The function has no antiderivative on the specified region. Thanks from alexmath

 Tags improper, integral

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post unwisetome3 Calculus 2 April 8th, 2013 10:45 AM mathrookie2012 Calculus 7 April 21st, 2012 08:14 PM chapsticks Calculus 1 February 26th, 2012 11:59 AM citbquinn Calculus 2 March 15th, 2011 10:42 AM izseekzu Calculus 1 April 13th, 2010 03:37 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top