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 October 18th, 2008, 08:12 AM #1 Member   Joined: Oct 2008 Posts: 34 Thanks: 0 help / functions does anyone help me? f(x)=4sin^-1(1-x^2)^1/2 what is its range?? and define the inverse of f
 October 19th, 2008, 04:32 AM #2 Global Moderator   Joined: Dec 2006 Posts: 21,038 Thanks: 2274 Its range is [0, 2pi]. It doesn't have an inverse unless its domain is restricted. If the domain is x ? 0, for example, the inverse function is cos(x/4), where 0 ? x ? 2pi.
 October 19th, 2008, 10:07 AM #3 Member   Joined: Oct 2008 Posts: 34 Thanks: 0 Re: help / functions so what is the answer?
October 21st, 2008, 03:48 AM   #4
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Quote:
 Originally Posted by skipjack Its range is [0, 2pi]. It doesn't have an inverse unless its domain is restricted. If the domain is x ? 0, for example, the inverse function is cos(x/4), where 0 ? x ? 2pi.
let the domain [0,1] so what is its range?

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