October 18th, 2008, 08:12 AM  #1 
Member Joined: Oct 2008 Posts: 34 Thanks: 0  help / functions
does anyone help me? f(x)=4sin^1(1x^2)^1/2 what is its range?? and define the inverse of f 
October 19th, 2008, 04:32 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 21,038 Thanks: 2274 
Its range is [0, 2pi]. It doesn't have an inverse unless its domain is restricted. If the domain is x ? 0, for example, the inverse function is cos(x/4), where 0 ? x ? 2pi. 
October 19th, 2008, 10:07 AM  #3 
Member Joined: Oct 2008 Posts: 34 Thanks: 0  Re: help / functions
so what is the answer?

October 21st, 2008, 03:48 AM  #4  
Member Joined: Oct 2008 Posts: 34 Thanks: 0  Re: Quote:
 

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