March 11th, 2014, 02:06 PM  #1 
Member Joined: Jan 2014 Posts: 40 Thanks: 0  calculating direction of tangent
a) Given the function g(x) = sin^2(x), what is the direction of its tangent at some x =xo? I seem to be running into trouble with this one. I have used a value of 5 for x. using this formula yf(xo)= f'(xo)(xxo) f'=2(sinx)(cosx) sub for 5 and get 0.544 f(x) at 5 = 0.9195 Thus far I have y0.9195 = .544(x5) y0.9195= 0.544x + 2.72 y= 0.544x+3.64 When I plot this function I have a slope the looks around .5 but why am I getting +3.64? 
March 11th, 2014, 07:41 PM  #2 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,600 Thanks: 2588 Math Focus: Mainly analysis and algebra  Re: calculating direction of tangent 
March 11th, 2014, 11:21 PM  #3 
Member Joined: Jan 2014 Posts: 40 Thanks: 0  Re: calculating direction of tangent
Thank you very much, makes perfect sense!


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