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 Calculus Calculus Math Forum

 January 9th, 2014, 06:20 AM #1 Senior Member   Joined: Sep 2013 From: Earth Posts: 827 Thanks: 36 Gradient function. The gradient function of a curve is px^2-qx, where p and q are constants. The curve has a turning point at (2,- . The gradient of the tangent to the curve at the point where its x-coordinate =-1 is 8. Find the values of p and q , The equation of the curve January 9th, 2014, 12:51 PM #2 Math Team   Joined: Sep 2007 Posts: 2,409 Thanks: 6 Re: Gradient function. That's pretty straight forward, isn't it? "The gradient of the function is ".\ So the function itself is of the form for constants p, q, and c. "The gradient of the tangent to the curve at the point where its x-coordinate =-1 is 8." Okay, the gradient is so we must have . "The curve has a turning point at (2,- ." That tells us two things. First when x= 2, y= -8 so . Also since it is a turning point, the derivative is 0: . Solve those three equations for p, q, and c. It would probably be easiest to solve p+ q= 8 and 4p- 2q= 0 for p and q first, then solve the third equation for c. Tags function, gradient Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post jiasyuen Calculus 5 January 9th, 2014 10:55 AM jiasyuen Calculus 3 January 9th, 2014 02:27 AM BenR Calculus 0 December 12th, 2012 01:33 AM Wooseok Nam Applied Math 0 May 20th, 2010 12:44 AM Mediocre1981 Calculus 3 August 29th, 2008 03:01 AM

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