My Math Forum Length of the Asteroid

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 October 5th, 2008, 09:14 AM #1 Senior Member   Joined: Sep 2008 Posts: 105 Thanks: 0 Length of the Asteroid Find the length of the asteroid x^(2/3) + y ^(2/3) = 1. How can I do this without limits? Using the arc length formula, I came up with (3/2) x ^ (2/3) after integrating. Now what?
 October 5th, 2008, 09:41 AM #2 Guest   Joined: Posts: n/a Thanks: Re: Length of the Asteroid Solving for y we get: $y=\left(1-x^{\frac{2}{3}}\right)^{\frac{3}{2}}$ Find the derivative, square it, add 1 and take the square root. And it whittles down to $\frac{1}{x^{\frac{1}{3}}}$ BTW, it is an 'astroid'. No e
 October 5th, 2008, 11:28 AM #3 Senior Member   Joined: Sep 2008 Posts: 105 Thanks: 0 Re: Length of the Asteroid Got it. Thanks! We never went over that in class, and it just appeared on our take-home. And thanks for the correction. The professor tends to mix up words. He once went through a lecture with the word "anti-semitic" on the board instead of "anti-symmetric".

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# find the length of the asteroid x^2/3 y^2/3=a^2/3

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