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 October 30th, 2013, 07:13 PM #1 Senior Member   Joined: Apr 2013 From: Ramallah, Palestine Posts: 349 Thanks: 0 State the domain Can someone check my work? Consider the function$f(x)= \frac{x^2}{\sqrt{x + 1}}$ a) State the domain. My solution: $x + 1 >= 0 x >= -1$ domain is : x >= -1 b) Find the intercepts. $\frac{0^2}{\sqrt{0 + 1}}=$ 0, so y = 0. then; $x^2 = 0 x = 0$. so x intercept = 0 and y intercept = 0. c)Find the hroizontal and vertical asymptotes if they exist. How do I do this? d) Determine intervals on which function is increasing/decreasing Ok so I take derivative and get $2x * (x + 1)^{1/2} - x^2 * \frac{1}{2} / (x + 1)$ so now this simplifies to?
October 30th, 2013, 08:39 PM   #2
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Re: State the domain

Quote:
 Originally Posted by Shamieh Can someone check my work? Consider the function$f(x)= \frac{x^2}{\sqrt{x + 1}}$ a) State the domain. My solution: $x + 1 >= 0 x >= -1$ domain is : x >= -1
Actually, the denominator cannot be zero, so it is a strict inequality.

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