October 13th, 2013, 08:19 AM  #1 
Newbie Joined: Oct 2013 Posts: 13 Thanks: 0  Inverse laplace transform
Hi, I am trying to do the inverse Laplace transform for this equation I arrived at with partial fractions. Two of the terms have complex numbers in them and I see that they are simplified to Cos and Sin terms from their exponential form (the process is quoted as 'Eulers identity'). Could somebody explain how this process is carried out? L^1 : 5*(1+j)/(s+j500) and 5*(1j)/(s+j500) The inverse of these I have as (1+j)e^(j500*t) and (1j)e^(j500*t) respectively (I hope that is correct!) Where my total equation is equal to these two terms and one other noncomplex exponential term added together (it is for current in a resistor inductor circuit with a sinusoidal source voltage). Many thanks, Ryan 
October 13th, 2013, 05:23 PM  #2 
Senior Member Joined: Jul 2012 From: DFW Area Posts: 635 Thanks: 96 Math Focus: Electrical Engineering Applications  Re: Inverse laplace transform
Hi Rydog21, I believe that you need to use Euler's Formula: I also think that there is a misstatement in your problem. The reason is that the denominators are both the same but the signs of the exponents in the Inverse Laplace Transform are opposite. I will assume that you meant to find: Given that: we get: [1] By Euler's formula, we can write as and we can write as Substituting these into the right hand side of equation [1] we get: Using Euler's Formula again, this reduces to: Since the imaginary terms cancel and the real terms add giving: Note, of course, that could be replaced with 
October 15th, 2013, 09:35 AM  #3 
Newbie Joined: Oct 2013 Posts: 13 Thanks: 0  Re: Inverse laplace transform
Thanks for that, I understand now. You're the man.


Tags 
inverse, laplace, transform 
Search tags for this page 
Click on a term to search for related topics.

Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Inverse Laplace transform  Asmir  Complex Analysis  2  August 18th, 2013 05:49 AM 
inverse laplace transform  capea  Complex Analysis  5  August 3rd, 2013 02:30 PM 
Laplace tranform and inverse of Laplace transform  Deiota  Calculus  1  April 28th, 2013 10:28 AM 
inverse laplace transform  defunktlemon  Real Analysis  1  April 14th, 2012 02:19 PM 
Inverse Laplace Transform  timh  Applied Math  1  June 7th, 2010 06:44 PM 