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 October 4th, 2013, 08:03 PM #1 Senior Member   Joined: Apr 2013 From: Ramallah, Palestine Posts: 349 Thanks: 0 Find the equation of the tangent line (3) Find the equation of the tangent line to $y= (3-2x)^9 at (1,1)$ Can someone check my work? $y' = 9(3-2x) * (-2) y' = 9(3) * -2 y' = 27 * -2 m = 54 y - 1 = 54(x - 1) = 54 -54 + 1 = 54 = 53 = 1 y = 1$?
 October 4th, 2013, 11:48 PM #2 Senior Member   Joined: Dec 2012 Posts: 372 Thanks: 2 Re: Find the equation of the tangent line (3) You wrongly computed the derivative and then made a substitution error. $y= (3 - 2x)^9 \ \Rightarrow \ y#39; = -18(3 - 2x)^8$ Please confirm this. Next, substitute $x= 1$ in the expression for $y'$ to get -18 not 54. The equation for your line is $y-1= -18(x-1)$. I hope you were sleepy when doing this post - otherwise, I must say you're being sloppy.

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