September 6th, 2013, 10:18 PM  #1 
Senior Member Joined: Jul 2011 Posts: 399 Thanks: 15  Indefinite Integration 
September 6th, 2013, 11:39 PM  #2 
Senior Member Joined: Aug 2011 Posts: 334 Thanks: 8  Re: Indefinite Integration 
September 7th, 2013, 08:45 AM  #3  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407  Re: Indefinite Integration Hello, panky! This requires an inordinate amount of work . . . Quote: [color=beige] .[/color][color=blue][1][/color] ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ [color=beige] .[/color][color=blue][2][/color] ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~  
September 7th, 2013, 09:05 AM  #4 
Math Team Joined: Sep 2007 Posts: 2,409 Thanks: 6  Re: Indefinite Integration
Personally, I, being terrified of all trig functions other than sine and cosine, would have immediately written this as . That has an odd power of cosine so multiply both numerator and denominator by cos(x) to get . Now, let u= sin(x) so that du= cos(x) dx and the integral becomes which can be done by "partial fractions".

September 23rd, 2013, 08:42 AM  #5 
Senior Member Joined: Jul 2011 Posts: 399 Thanks: 15  Re: Indefinite Integration
Thanks soroban and HallsofIvy Got it


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