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August 21st, 2019, 12:11 AM  #1 
Newbie Joined: Aug 2019 From: India Posts: 15 Thanks: 0  Calculating the volume under the intersection of three orthogonal cylinders by slices
I have three cylinders : $\displaystyle x^2 + y^2 = 1 $ $\displaystyle y^2 + z^2 = 1 $ $\displaystyle x^2 + z^2 = 1 $ Now all these intersect orthogonally at the origin and I need to find the volume of than enclosure. My problem is I'm not able to do it by slicing method. See what I'm trying to do is finding the intersection points first : $\displaystyle x^2 + y^2 = y^2 + z^2 $ since both equal to 1 therefore, $\displaystyle x = z$ Now, $\displaystyle 2 z^2 = 1 $ implies $\displaystyle z = plus/minus \sqrt{1/2} $ So, endpoints of the figure are $\displaystyle x = [\sqrt {1/2} , \sqrt{1/2}] , y= \sqrt{1/2}, \sqrt{1/2}], z = [\sqrt{1/2}, \sqrt{1/2}] $ Now I know that to find volume we have to integrate twice, but I can't figure out what we have to integrate, I have attached the figure. I want to know how can we proceed with slicing. Thank you, any help will be much appreciated. 
August 21st, 2019, 12:40 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,972 Thanks: 2222 
You might find this article useful.

August 21st, 2019, 04:49 AM  #3 
Newbie Joined: Aug 2019 From: India Posts: 15 Thanks: 0 
Wikipedia explains it for two cylinders but when it comes to three cylinders it just says “we use the same argument as before”. Can you please give a hint about slicing ?


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calculating, cylinders, intersection, orthogonal, slices, volume 
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