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 August 13th, 2019, 01:49 AM #1 Newbie   Joined: Apr 2019 From: Malawi Posts: 19 Thanks: 0 Math Focus: Trigonometry and calculus Calculus Find the area of the region bounded above by y=x, and bounded below by y=x^2 and bounded on the sides by x=0 and x=1. HELP PLEASE!
 August 13th, 2019, 02:39 AM #2 Math Team     Joined: Jul 2011 From: Texas Posts: 3,031 Thanks: 1620 $\displaystyle A = \int_0^1 x-x^2 \, dx$ evaluate the definite integral ... Thanks from topsquark
August 13th, 2019, 03:09 AM   #3
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Quote:
 Originally Posted by skeeter $\displaystyle A = \int_0^1 x-x^2 \, dx$ evaluate the definite integral ...
Pet peeve alert! Danger! Danger Will Robinson!

I would write that as
$\displaystyle \int_0^1 (x - x^2) ~ dx$

I know skeeter's version is a common notation but as it's my birthday I'm allowed to write it this way. Thhhhpppttt!

-Dan

August 13th, 2019, 04:13 AM   #4
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Quote:
 Originally Posted by topsquark ... it's my birthday I'm allowed to write it this way. Thhhhpppttt! -Dan
Party on, Dan

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