My Math Forum Fully defined integrals
 User Name Remember Me? Password

 Calculus Calculus Math Forum

 July 8th, 2019, 07:52 AM #1 Newbie   Joined: Jul 2019 From: Romania Posts: 1 Thanks: 0 Fully defined integrals Hello! So I've got this integral: https://prnt.sc/oc6zok And I managed to get to this result : I(n)=x^(n)(sinx)+n(x^(n-1))(cosx)—n(n-1){I(n-2)} However, since the integral is defined on the interval (-pi,pi) I don't know how to continue. Excuse my English for I am not a native English speaker and I'm not used to utilize mathematical terms in this language.I basically don't know how to proceed further.I know that somehow I've got to give x the values of -pi and pi but I don't know how to get to that point.
 July 8th, 2019, 12:32 PM #2 Math Team     Joined: Jul 2011 From: Texas Posts: 2,980 Thanks: 1573 $\displaystyle I(n) = \int_{-\pi}^\pi x^n \cos{x} \, dx$ for $n \in \{2,3 \}$ $I(3) = 0$ because the integrand, $x^3\cos{x}$, is an odd function symmetric to the origin. For $n=2$, the integrand, $x^2\cos{x}$, is an even function. Even functions have symmetry across the y-axis ... $\displaystyle I(2) = 2\int_0^\pi x^2 \cos{x} \, dx = 2\bigg[-x^2\sin{x}+2x\cos{x}+2\sin{x}\bigg]_0^\pi = 2\bigg[(-2\pi) - (0) \bigg] =-4\pi$ Thanks from topsquark

 Tags defined, fully, integrals

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post dennisdixon New Users 8 March 3rd, 2013 07:09 AM durky Abstract Algebra 6 March 28th, 2012 01:29 PM probiner Algebra 4 February 17th, 2012 11:49 AM jonas Algebra 1 November 12th, 2009 10:55 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top

Copyright © 2019 My Math Forum. All rights reserved.