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July 9th, 2019, 05:12 PM   #21
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triangle area = base × height / 2 = height / 2 if the base has length 1.
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July 9th, 2019, 05:12 PM   #22
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Originally Posted by EvanJ View Post
I understand that, but what I don't know is how the left term of the inequality produced (sin x)/2 and how the right term produced (tan x)/2. Angle AEB is right, but isn't in those triangles.

area of triangle ABD < area of sector ABD < area of triangle AFD
triangle ABD ... base = 1, height = sin x

triangle AFD ... base = 1, height = tan x

A = (1/2)bh

Last edited by skipjack; July 12th, 2019 at 04:19 AM.
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July 11th, 2019, 04:20 PM   #23
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You can check it by using Taylor series.
It will give you the answer in an easy way.

Last edited by skipjack; July 12th, 2019 at 04:19 AM.
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show, sinx or x, x&gt0, x>0

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