May 6th, 2019, 10:11 PM  #1 
Member Joined: Apr 2017 From: India Posts: 64 Thanks: 0  Mean value theorem
With the help of mean value theorem, for x>0, 0<theta<1, how we can express log(x+1){base 10} in terms of theta? The answer given is: x loge(base10)/1+theta(x) 
May 7th, 2019, 01:20 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,755 Thanks: 695 
You haven't defined $\theta$ for this expression.


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