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May 6th, 2019, 10:11 PM   #1
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Mean value theorem

With the help of mean value theorem, for x>0, 0<theta<1, how we can express log(x+1){base 10} in terms of theta?

The answer given is: x loge(base10)/1+theta(x)
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May 7th, 2019, 01:20 PM   #2
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You haven't defined $\theta$ for this expression.
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