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April 2nd, 2019, 08:16 AM   #1
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Math Focus: सामान्य गणित
Partial derivative

Find $\displaystyle \frac{\partial z}{\partial x}$ for $\displaystyle x^{2}+\cos y +z^{3}=1 $

Please explain what it means.
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April 2nd, 2019, 10:34 AM   #2
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Two ways to find it. (1) Just find the partial derivative to both sides of equality. (2) Write z explicitly and find the partial derivative.

Also $\displaystyle \partial z =(\partial z / \partial x )\cdot dx+(\partial z / \partial y )\cdot dy $.

Last edited by skipjack; April 2nd, 2019 at 02:26 PM.
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April 2nd, 2019, 12:55 PM   #3
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Start with $z=(1-x^2-\cos y)^\frac{1}{3}$.
Thanks from topsquark

Last edited by skipjack; April 2nd, 2019 at 02:27 PM.
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