My Math Forum  

Go Back   My Math Forum > College Math Forum > Calculus

Calculus Calculus Math Forum


Thanks Tree1Thanks
  • 1 Post By mathman
Reply
 
LinkBack Thread Tools Display Modes
April 2nd, 2019, 08:16 AM   #1
Math Team
 
MATHEMATICIAN's Avatar
 
Joined: Jul 2013
From: काठमाडौं, नेपाल

Posts: 880
Thanks: 60

Math Focus: सामान्य गणित
Partial derivative

Find $\displaystyle \frac{\partial z}{\partial x}$ for $\displaystyle x^{2}+\cos y +z^{3}=1 $

Please explain what it means.
MATHEMATICIAN is offline  
 
April 2nd, 2019, 10:34 AM   #2
Senior Member
 
Joined: Dec 2015
From: iPhone

Posts: 486
Thanks: 75

Two ways to find it. (1) Just find the partial derivative to both sides of equality. (2) Write z explicitly and find the partial derivative.

Also $\displaystyle \partial z =(\partial z / \partial x )\cdot dx+(\partial z / \partial y )\cdot dy $.

Last edited by skipjack; April 2nd, 2019 at 02:26 PM.
idontknow is offline  
April 2nd, 2019, 12:55 PM   #3
Global Moderator
 
Joined: May 2007

Posts: 6,732
Thanks: 689

Start with $z=(1-x^2-\cos y)^\frac{1}{3}$.
Thanks from topsquark

Last edited by skipjack; April 2nd, 2019 at 02:27 PM.
mathman is offline  
Reply

  My Math Forum > College Math Forum > Calculus

Tags
derivative, partial



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
How do I take this partial derivative? shreddinglicks Calculus 3 October 16th, 2014 04:28 PM
Partial derivative Dmath Calculus 3 May 6th, 2014 01:08 AM
How to get this partial derivative? artiny Calculus 2 November 10th, 2013 12:36 PM
partial derivative help gth759k Calculus 5 June 10th, 2011 09:12 PM
Partial derivative Ducky831 Calculus 1 October 23rd, 2009 03:48 PM





Copyright © 2019 My Math Forum. All rights reserved.