April 2nd, 2019, 08:16 AM  #1 
Math Team Joined: Jul 2013 From: काठमाडौं, नेपाल Posts: 880 Thanks: 60 Math Focus: सामान्य गणित  Partial derivative
Find $\displaystyle \frac{\partial z}{\partial x}$ for $\displaystyle x^{2}+\cos y +z^{3}=1 $ Please explain what it means. 
April 2nd, 2019, 10:34 AM  #2 
Senior Member Joined: Dec 2015 From: iPhone Posts: 486 Thanks: 75 
Two ways to find it. (1) Just find the partial derivative to both sides of equality. (2) Write z explicitly and find the partial derivative. Also $\displaystyle \partial z =(\partial z / \partial x )\cdot dx+(\partial z / \partial y )\cdot dy $. Last edited by skipjack; April 2nd, 2019 at 02:26 PM. 
April 2nd, 2019, 12:55 PM  #3 
Global Moderator Joined: May 2007 Posts: 6,732 Thanks: 689 
Start with $z=(1x^2\cos y)^\frac{1}{3}$.
Last edited by skipjack; April 2nd, 2019 at 02:27 PM. 

Tags 
derivative, partial 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
How do I take this partial derivative?  shreddinglicks  Calculus  3  October 16th, 2014 04:28 PM 
Partial derivative  Dmath  Calculus  3  May 6th, 2014 01:08 AM 
How to get this partial derivative?  artiny  Calculus  2  November 10th, 2013 12:36 PM 
partial derivative help  gth759k  Calculus  5  June 10th, 2011 09:12 PM 
Partial derivative  Ducky831  Calculus  1  October 23rd, 2009 03:48 PM 