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March 26th, 2019, 06:27 PM   #11
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Originally Posted by Leonardox View Post
I finished all understanding perfectly. the rest of the world that is exactly what I was meaning thanks for solid example.
you are unfortunately in the second group SDK deal with the fact.
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March 26th, 2019, 06:28 PM   #12
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Quote:
Originally Posted by Leonardox View Post
I finished all understanding perfectly. the rest of the world that is exactly what I was meaning thanks for solid example.
Ya know... my example is wrong :P

It should show that

$f^{(n)}(0) = n!$

which cancels with the $n!$ in the denominator of the series that I
omitted in error.

I knew I had the series right due to software but I got it wrong as to why.

I'm glad you were still able to find the example useful.

I'd kind of appreciate it if you didn't compare me with others on here.

We all have different strengths and some of the others folks strengths are strong indeed.
Thanks from topsquark and Leonardox

Last edited by romsek; March 26th, 2019 at 06:31 PM.
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March 26th, 2019, 08:30 PM   #13
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Originally Posted by Leonardox View Post
and like you, who is suspicous to have knowledge but definitely no academic capacity to explain anything but critize with assumption.
Like me? You never did answer my question about the value for a. Since you like romsek's answer can I presume that means you need to take a = 0?

-Dan
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