My Math Forum Limit Calculation

 Calculus Calculus Math Forum

 February 23rd, 2019, 07:55 AM #1 Newbie   Joined: Jan 2019 From: Athens Posts: 5 Thanks: 0 Limit Calculation Hi, I am trying to solve the following limit $\displaystyle \lim_{x\to\infty}\cos\left(\!\frac{\pi\sqrt{x^4 + 7}}{6x^2 + 5}\right)$ https://drive.google.com/open?id=1ll...XvBmLta1ozBcCW Any help is welcome!! Last edited by skipjack; March 26th, 2019 at 12:49 AM.
 February 23rd, 2019, 08:35 AM #2 Senior Member   Joined: Dec 2015 From: somewhere Posts: 647 Thanks: 94 You can set the limit inside the $\displaystyle \cos$-function . Thanks from topsquark
 February 23rd, 2019, 05:56 PM #3 Senior Member     Joined: Sep 2015 From: USA Posts: 2,554 Thanks: 1403 $\lim \limits_{x\to \infty} \cos\left(\dfrac{\pi \sqrt{x^4+7}}{6x^2+5}\right) =$ $\lim \limits_{x\to \infty} \cos\left(\dfrac{\pi \sqrt{1+7x^{-4}}}{6+5x^{-2}}\right) =$ $\cos\left(\dfrac{\pi}{6}\right) = \dfrac{\sqrt{3}}{2}$ Thanks from topsquark

 Tags calculation, limit

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post shenlong1234 Calculus 2 December 8th, 2016 04:21 AM evol_w10lv Calculus 2 April 25th, 2016 02:56 PM icemanfan Real Analysis 3 September 10th, 2012 12:02 PM patient0 Real Analysis 14 January 19th, 2011 05:17 AM Crouch Calculus 2 December 30th, 2010 02:39 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top