User Name Remember Me? Password

 Calculus Calculus Math Forum

 February 23rd, 2019, 07:55 AM #1 Newbie   Joined: Jan 2019 From: Athens Posts: 5 Thanks: 0 Limit Calculation Hi, I am trying to solve the following limit $\displaystyle \lim_{x\to\infty}\cos\left(\!\frac{\pi\sqrt{x^4 + 7}}{6x^2 + 5}\right)$ https://drive.google.com/open?id=1ll...XvBmLta1ozBcCW Any help is welcome!! Last edited by skipjack; March 26th, 2019 at 12:49 AM. February 23rd, 2019, 08:35 AM #2 Senior Member   Joined: Dec 2015 From: somewhere Posts: 647 Thanks: 94 You can set the limit inside the $\displaystyle \cos$-function . Thanks from topsquark February 23rd, 2019, 05:56 PM #3 Senior Member   Joined: Sep 2015 From: USA Posts: 2,554 Thanks: 1403 $\lim \limits_{x\to \infty} \cos\left(\dfrac{\pi \sqrt{x^4+7}}{6x^2+5}\right) =$ $\lim \limits_{x\to \infty} \cos\left(\dfrac{\pi \sqrt{1+7x^{-4}}}{6+5x^{-2}}\right) =$ $\cos\left(\dfrac{\pi}{6}\right) = \dfrac{\sqrt{3}}{2}$ Thanks from topsquark Tags calculation, limit Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post shenlong1234 Calculus 2 December 8th, 2016 04:21 AM evol_w10lv Calculus 2 April 25th, 2016 02:56 PM icemanfan Real Analysis 3 September 10th, 2012 12:02 PM patient0 Real Analysis 14 January 19th, 2011 05:17 AM Crouch Calculus 2 December 30th, 2010 02:39 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top      