January 31st, 2019, 05:10 AM  #1 
Member Joined: Apr 2017 From: India Posts: 45 Thanks: 0  Integration
Integrate the function in the attachment.

January 31st, 2019, 05:20 AM  #2 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,600 Thanks: 2588 Math Focus: Mainly analysis and algebra 
Are you giving instructions or asking for help? If you want help, I suggest that you say what is giving you trouble with this integral. It has come to your attention in some context, presumably a class  so I would suggest trying to apply the lessons of that class to this problem. If you get stuck, you can always post your work as you did the question, and ask for help. 
January 31st, 2019, 05:31 AM  #3 
Senior Member Joined: Dec 2015 From: iPhone Posts: 387 Thanks: 61 
Substitute $\displaystyle x=a\sin(t)$.
Last edited by skipjack; January 31st, 2019 at 06:24 AM. 
January 31st, 2019, 06:32 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 20,298 Thanks: 1971  
January 31st, 2019, 06:32 AM  #5  
Member Joined: Apr 2017 From: India Posts: 45 Thanks: 0  Quote:
 
January 31st, 2019, 07:30 AM  #6 
Global Moderator Joined: Dec 2006 Posts: 20,298 Thanks: 1971 
It's a standard problem (one that can be done by use of the methods given in a typical introductory calculus textbook), but you shouldn't be expected to do it without first having learnt how to use a trigonometric substitution for an easier integral. Can you try the suggested substitution and then let us know what progress you were able to make? 

Tags 
integration 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Lebesgue integration  Riemann integration  shaharhada  Calculus  3  July 13th, 2018 10:01 AM 
recursive integration,integration done, how to get formula  Lazar  Calculus  1  December 28th, 2014 01:40 PM 
Integration and Sum?  billyford  Calculus  2  February 24th, 2014 03:33 PM 
integration  jefferson_lc  Real Analysis  1  February 13th, 2011 07:27 PM 
Why this integration comes out to be zero always  faraday007  Calculus  1  January 23rd, 2011 04:05 AM 