January 12th, 2019, 12:44 AM  #1 
Newbie Joined: Jan 2019 From: London Posts: 2 Thanks: 0  Double integral
How to evaluate this double integral: $\displaystyle \int_{x=0}^{x=\pi}\int_{y=0}^{y=2\pi}\frac{A^{2}B^ {2}C^{2}\sin x}{\left(A^{2}B^{2}\cos^{2}x+A^{2}C^{2}\sin^{2}x \sin^{2}y+B^{2}C^{2}\sin^{2}x\cos^{2}y\right)^{3/2}}dydx$ where $\displaystyle A,B,C$ are constants. 
January 12th, 2019, 08:04 AM  #2 
Banned Camp Joined: Mar 2015 From: New Jersey Posts: 1,720 Thanks: 126 
The x portion is of the form: $\displaystyle \int \frac{a\sin x}{(b +c\cos^{2} x)^{\frac{3}{2}}}dx$ Substitute u=cos x and look it up in a table of integrals. The rest should fall into place. 

Tags 
calculus, double, double integral, integral 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Double integral, repeated integral and the FTC  Jhenrique  Calculus  5  June 30th, 2015 03:45 PM 
Help with double integral  JORGEMAL  Calculus  3  December 4th, 2013 12:41 PM 
integral of double integral in a region E  maximus101  Calculus  0  March 4th, 2011 01:31 AM 
a double integral  Reis  Calculus  1  March 22nd, 2009 10:18 AM 
integral of double integral in a region E  maximus101  Algebra  0  December 31st, 1969 04:00 PM 