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 January 12th, 2019, 12:44 AM #1 Newbie   Joined: Jan 2019 From: London Posts: 2 Thanks: 0 Double integral How to evaluate this double integral: $\displaystyle \int_{x=0}^{x=\pi}\int_{y=0}^{y=2\pi}\frac{A^{2}B^ {2}C^{2}\sin x}{\left(A^{2}B^{2}\cos^{2}x+A^{2}C^{2}\sin^{2}x \sin^{2}y+B^{2}C^{2}\sin^{2}x\cos^{2}y\right)^{3/2}}dydx$ where $\displaystyle A,B,C$ are constants. January 12th, 2019, 08:04 AM #2 Banned Camp   Joined: Mar 2015 From: New Jersey Posts: 1,720 Thanks: 126 The x portion is of the form: $\displaystyle \int \frac{a\sin x}{(b +c\cos^{2} x)^{\frac{3}{2}}}dx$ Substitute u=cos x and look it up in a table of integrals. The rest should fall into place. Thanks from idontknow Tags calculus, double, double integral, integral Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Jhenrique Calculus 5 June 30th, 2015 03:45 PM JORGEMAL Calculus 3 December 4th, 2013 12:41 PM maximus101 Calculus 0 March 4th, 2011 01:31 AM Reis Calculus 1 March 22nd, 2009 10:18 AM maximus101 Algebra 0 December 31st, 1969 04:00 PM

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