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December 1st, 2018, 12:23 PM   #1
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Prove that

If xy^2=(x+y)^3
prove that:
x^2y''-xy'+y=0
fahad nasir is offline  
 
December 1st, 2018, 04:26 PM   #2
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If y/x is real, solving xy² = (x + y)³ gives y = cx, where c is a constant (equal to approximately -0.43).

It's easy to show that y = cx, where c is a constant, is a solution of x²y'' - xy' + y = 0.
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