November 9th, 2018, 09:01 AM  #1 
Newbie Joined: Sep 2018 From: Spain Posts: 11 Thanks: 0  Limits
need these 2 solved lim x>1 (x^3  x^2  x  1)= lim (3x^2 + 4x  2)= x>00(infinity) 
November 9th, 2018, 09:48 AM  #2 
Senior Member Joined: May 2016 From: USA Posts: 1,310 Thanks: 551  
November 9th, 2018, 09:55 AM  #3 
Newbie Joined: Sep 2018 From: Spain Posts: 11 Thanks: 0 
Yes, I have, but these two still have me a bit confused. Last edited by skipjack; November 9th, 2018 at 06:19 PM. 
November 9th, 2018, 10:07 AM  #4 
Senior Member Joined: Oct 2009 Posts: 784 Thanks: 280  What did you get after applying the law of limits? Can you explain why you are confused?
Last edited by skipjack; November 9th, 2018 at 06:19 PM. 
November 9th, 2018, 10:09 AM  #5 
Newbie Joined: Sep 2018 From: Spain Posts: 11 Thanks: 0 
The x and the 3 confuses me.
Last edited by skipjack; November 9th, 2018 at 06:20 PM. 
November 9th, 2018, 02:36 PM  #6 
Senior Member Joined: Oct 2009 Posts: 784 Thanks: 280 
Can you tell us what you tried?
Last edited by skipjack; November 9th, 2018 at 06:20 PM. 
November 9th, 2018, 06:30 PM  #7 
Global Moderator Joined: Dec 2006 Posts: 20,648 Thanks: 2085 
x^3 is equivalent to (x³), etc. If $p(x)$ is a nonconstant polynomial in $x$, $\displaystyle \lim_{x\to\infty}p(x)$ doesn't exist (strictly speaking), and $\displaystyle \lim_{x\to k}p(x) = p(k)$. 

Tags 
limits 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Limits  Nazar  PreCalculus  4  August 24th, 2014 04:54 PM 
new to limits help!  harryjobs  Calculus  6  June 15th, 2014 09:59 PM 
More Limits  Arley  Calculus  2  April 1st, 2012 10:12 AM 
Limits,Finding functions by limits  kadmany  Calculus  9  March 18th, 2011 06:16 AM 
Limits  lilwayne  Calculus  18  September 23rd, 2010 02:39 PM 