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 November 9th, 2018, 09:01 AM #1 Newbie   Joined: Sep 2018 From: Spain Posts: 11 Thanks: 0 Limits need these 2 solved lim x-->1 (-x^3 - x^2 - x - 1)= lim (-3x^2 + 4x - 2)= x-->00(infinity)
November 9th, 2018, 09:48 AM   #2
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Quote:
 Originally Posted by raven2k7 need these 2 solved lim x-->1 (-x^3 - x^2 - x - 1)= lim (-3x^2 + 4x - 2)= x-->00(infinity)
So what have you tried to do so far?

Have you applied the laws of limits as I suggested in a prior post?

 November 9th, 2018, 09:55 AM #3 Newbie   Joined: Sep 2018 From: Spain Posts: 11 Thanks: 0 Yes, I have, but these two still have me a bit confused. Last edited by skipjack; November 9th, 2018 at 06:19 PM.
November 9th, 2018, 10:07 AM   #4
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Quote:
 Originally Posted by raven2k7 Yes, I have, but these two still have me a bit confused.
What did you get after applying the law of limits? Can you explain why you are confused?

Last edited by skipjack; November 9th, 2018 at 06:19 PM.

 November 9th, 2018, 10:09 AM #5 Newbie   Joined: Sep 2018 From: Spain Posts: 11 Thanks: 0 The -x and the -3 confuses me. Last edited by skipjack; November 9th, 2018 at 06:20 PM.
 November 9th, 2018, 02:36 PM #6 Senior Member   Joined: Oct 2009 Posts: 784 Thanks: 280 Can you tell us what you tried? Last edited by skipjack; November 9th, 2018 at 06:20 PM.
 November 9th, 2018, 06:30 PM #7 Global Moderator   Joined: Dec 2006 Posts: 20,648 Thanks: 2085 -x^3 is equivalent to -(x³), etc. If $p(x)$ is a non-constant polynomial in $x$, $\displaystyle \lim_{x\to\infty}p(x)$ doesn't exist (strictly speaking), and $\displaystyle \lim_{x\to k}p(x) = p(k)$.

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