My Math Forum a = f(n), da/dt = f(dn/dt)

 Calculus Calculus Math Forum

 August 4th, 2018, 03:48 PM #1 Newbie   Joined: Jun 2017 From: italia Posts: 13 Thanks: 2 a = f(n), da/dt = f(dn/dt) Let $a^3 = \frac{10096.676}{n^2}$. I know $a$, $n$ and $dn/dt$. Is there any way to calculate $da/dt$?
 August 4th, 2018, 04:50 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,913 Thanks: 1113 Math Focus: Elementary mathematics and beyond Differentiate implicitly $$3a^2\frac{da}{dt}=-\frac{20193.352}{n^3}\frac{dn}{dt}$$ and solve for $\frac{da}{dt}$. Thanks from topsquark, Country Boy and Cristiano
 August 5th, 2018, 03:29 AM #3 Newbie   Joined: Jun 2017 From: italia Posts: 13 Thanks: 2 Do you mean $$\frac{da}{dt}=-\frac{\frac{20193.352}{n^3}\frac{dn}{dt}}{3a^2}$$ ? The result seems good and the dimensional analysis is good (it's an astronomy problem). I should be reasonably sure that the formula I wrote in my program is correct. Thanks a lot! Thanks from greg1313 Last edited by Cristiano; August 5th, 2018 at 03:33 AM.
 August 5th, 2018, 05:07 AM #4 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,913 Thanks: 1113 Math Focus: Elementary mathematics and beyond That's it and you're welcome.

 Tags da or dt, fdn or dt

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