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July 10th, 2018, 10:04 AM  #1 
Newbie Joined: Oct 2017 From: Here Posts: 19 Thanks: 0  Taylor series of multiplied functions
I am having hard times trying to write the Taylor series of: x*(cos(2pi*x)) to 2nd order around the point a=1 What do I need to do? thanks 
July 10th, 2018, 10:43 AM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,910 Thanks: 774 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
The other way is to find the Taylor series of each individual function: $\displaystyle x = 1 + (x  1)$ $\displaystyle \cos( 2 \pi x) \approx 1 + 2 \pi^2 (x  1)^2 + \text{ ... }$ Multiply the two expressions and discard the term in (x  1)^3 and you'll get the expression for the whole thing given above. Dan Last edited by skipjack; July 10th, 2018 at 12:12 PM.  
July 10th, 2018, 10:46 AM  #3 
Newbie Joined: Oct 2017 From: Here Posts: 19 Thanks: 0 
Thanks, I was able to solve it!


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functions, multiplied, series, taylor 
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