
Calculus Calculus Math Forum 
 LinkBack  Thread Tools  Display Modes 
July 10th, 2018, 10:04 AM  #1 
Newbie Joined: Oct 2017 From: Here Posts: 19 Thanks: 0  Taylor series of multiplied functions
I am having hard times trying to write the Taylor series of: x*(cos(2pi*x)) to 2nd order around the point a=1 What do I need to do? thanks 
July 10th, 2018, 10:43 AM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,980 Thanks: 789 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
The other way is to find the Taylor series of each individual function: $\displaystyle x = 1 + (x  1)$ $\displaystyle \cos( 2 \pi x) \approx 1 + 2 \pi^2 (x  1)^2 + \text{ ... }$ Multiply the two expressions and discard the term in (x  1)^3 and you'll get the expression for the whole thing given above. Dan Last edited by skipjack; July 10th, 2018 at 12:12 PM.  
July 10th, 2018, 10:46 AM  #3 
Newbie Joined: Oct 2017 From: Here Posts: 19 Thanks: 0 
Thanks, I was able to solve it!


Tags 
functions, multiplied, series, taylor 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Taylor series  chuackl  Calculus  1  June 1st, 2014 07:47 PM 
In need of help disk, series test, taylor, and power series  g0bearmon  Real Analysis  2  May 22nd, 2012 01:10 PM 
Taylor series & trigonometric functions  goldenarms  Calculus  1  November 12th, 2009 02:36 PM 
Taylor Series of log(1t)  vjj  Number Theory  0  December 31st, 1969 04:00 PM 
In need of help disk, series test, taylor, and power series  g0bearmon  Calculus  1  December 31st, 1969 04:00 PM 